1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 | class MedianFinder { private PriorityQueue<Integer> minHeap; private PriorityQueue<Integer> maxHeap; public MedianFinder() { minHeap = new PriorityQueue<Integer>(); maxHeap = new PriorityQueue<Integer>( 500 , Collections.reverseOrder()); } // Adds a number into the data structure. public void addNum( int num) { if (maxHeap.size() == 0 || num <= maxHeap.peek()) { maxHeap.add(num); } else { minHeap.add(num); } if (maxHeap.size() - minHeap.size() >= 2 ) { minHeap.add(maxHeap.poll()); } else if (minHeap.size() > maxHeap.size()) { maxHeap.add(minHeap.poll()); } } // Returns the median of current data stream public double findMedian() { double median = 0 ; if (maxHeap.size() != 0 ) { if ((maxHeap.size() + minHeap.size()) % 2 != 0 ) { median = ( double ) maxHeap.peek(); } else { median = ( double ) (maxHeap.peek() + minHeap.peek()) / 2 ; } } return median; } }; |
Sunday, January 3, 2016
[LeetCode] Find Median from Data Stream
思路是使用一个minHeap和maxHeap。不知道有没有更好的方法。
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